I have dabbled in the statistic side of things, but I've only really grasped combination in a basic level, so I still need some things answered for me !

Anyway, what are the chances of taking the highest 9 values on the board (illustrated below with Tegens' game) to 12-box ?

Thank you !

You multiply the probability of each box:
So first box there are 13 boxes you can pick out of 22 (13/22), second box is 12 out of 21 etc.

Which works out to exactly 1 in 2261 (I think)

Thanks very much for that, Simon !

Wow... lucky, lucky, lucky is all I can say... and that's without mentioning the outcome

Well, that's the long way of calculating it. The shorter way is to get your scientific calculator (or Google) to work out 13C10 (the number of combinations for picking 10 boxes, only from the lowest 13 amounts) and 22C10 (the number of combinations for picking 10 boxes from all 22 amounts). Then divide one by the other.

13C10 = 286
22C10 = 646646

So, out of the 646646 possible combinations at 12-box, 286 of them will have removed only amounts from £3000 downwards. And a 286 in 646646 chance does indeed simplify to 1 in 2261.

I was going to mention that way too but I didn't want to confuse.