i will be updating this regularly

Code:

5 blues 0 reds - None
4 blues 1 reds - 1
3 blues 2 reds - None
2 blues 3 reds - 9
1 blues 4 reds - 2
0 blues 5 reds - None

First 2 weeks

Please correct me if i have made any mistakes

I believe Emi got 5 blues and 0 reds?

I think Aaron is going from the start (game 1) and updating it?

It seems a little like the roll 2 dice and you will get 7/8/9 more often than 2 and 12.

Its also like, getting 3 reds and 2 blues (or other way round) is the most likely occurence, that does not mean it willl occur more than 50% of the time.

Yours looks right, and I don't want to steal your thunder or anything, but it took me a couple of minutes to do this on an Excel spreadsheet, so I thought I'd save you a bit of time

Both the all-red and all-blue final fives have occured less than we would expect statistically (we would expect 11 of each by now).

The 2 blues and 3 reds or 3 blues and 2 reds occurs very much.

I make the expected number about 6 of each...

ACTUAL PROBABILITIES (rounded to 1 decimal place)
5B 0R: 1.8%
4B 1R: 13.8%
3B 2R: 34.5%
2B 3R: 34.5%
1B 4R: 13.8%
0B 5R: 1.8%

So, in 343 games, the expected number of occurrences (each rounded to nearest whole number) are as follows...

5B 0R: 6 times
4B 1R: 47 times
3B 2R: 118 times
2B 3R: 118 times
1B 4R: 47 times
0B 5R: 6 times

This is indeed pretty close to what we've actually seen.

Thanks MisterAl

Was mistakenly working probability of 5 reds/blues as 1/(2x2x2x2x2).